A Sample of mixture of CaCl2 and NaCl weighing 4.44g was treated to precipitate all the Ca as CaCO3, which was then heated and quantitatively converted to 1.12g of CaO. (Atomic weight: Ca= 40, Na= 23, Cl= 35.5)
A
Mixture contains 50% NaCl
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B
Mixture contains 60% CaCl2
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C
Mass of CaCl2 is 2.22g
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D
Mass of CaCl2 is 1.11g
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Solution
The correct options are A Mixture contains 50% NaCl C Mass of CaCl2 is 2.22g Balanced reaction: CaCO30.02mole△−→CO2+CaO0.02mole
CaCl20.02moleNa2CO3−−−−−→CaCO30.02mole
mass of CaCl2 present in mixture =0.02×111=2.22g, which is %50 of the total mass, rest being `NaCl`