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Question

A Sample of mixture of CaCl2 and NaCl weighing 4.44 g was treated to precipitate all the Ca as CaCO3, which was then heated and quantitatively converted to 1.12 g of CaO. (Atomic weight: Ca= 40, Na= 23, Cl= 35.5)

A
Mixture contains 50% NaCl
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B
Mixture contains 60% CaCl2
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C
Mass of CaCl2 is 2.22 g
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D
Mass of CaCl2 is 1.11 g
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Solution

The correct options are
A Mixture contains 50% NaCl
C Mass of CaCl2 is 2.22 g
Balanced reaction:
CaCO30.02 moleCO2+CaO0.02 mole

CaCl20.02 moleNa2CO3−−−−CaCO30.02 mole

mass of CaCl2 present in mixture =0.02×111=2.22g, which is %50 of the total mass, rest being `NaCl`

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