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Introduction to Chemistry

A sample of n...

Question

A sample of neon occupies a volume of 461mL at STP. What will be the volume of the Ne when the pressure is reduced to 93.3 KPa.

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Solution

Dear Student

According to Boyle's Law,
P_i V_i = P_fV_f
when temperature is held constant

So, P_i = 101.3 kPa ; V_i = 461 ml
P_f = 93.3 kPa ; V_f = ?

Therefore, placing the values in equation, we get -
101.3 kPa * 461 ml = 93.3 kPa * V_f
So,
V_f = $\frac{101.3 k P a x 461 m l}{93.3 k P a}$ = 500.5 ml $\approx$ 501 ml

Therefore, the volume of Ne is 501 ml.

Regards

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