A sample of nitrogen occupies a volume of $350 {c m}^{3}$ at STP. Then, its volume at 550 K and 0.5 atm pressure is approximately:

1280 {c m}^{3}

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1409 {c m}^{3}

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1050 {c m}^{3}

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1428 {c m}^{3}

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Solution

The correct option is B $1409 {c m}^{3}$
$\frac{P_{1} V_{1}}{T_{2}}$ = $\frac{P_{2} V_{2}}{T_{2}}$
$P_{1} = 1 a t m$
$V_{1} = 350 c m^{3}$
$T_{1} = 273 k$
$P_{2} = 0.5 a t m$
$T_{2} = 550 k$
$V_{2} = ?$
$V_{2}$ = $\frac{P_{1} V_{1} T_{2}}{T_{1} P_{2}}$
$V_{2}$ =1 $\times$ 350 $\times$ 550 / 273 $\times$ 0.5
$V_{2}$ = 1409 $c m^{3}$
Therefore B is the correct option.

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