Question

A sample of oxygen occupies a volume of $160d{m}^3$ at ${91}^{\circ }C$. What will be volume of oxygen when the temperature drops to ${0.00}^{\circ }C$.? (Pressure remains constant)

• A. $120d{m}^3$
• B. $400d{m}^3$
• C. $387d{m}^3$
• D. $551d{m}^3$

Answer 1

The correct option is A

$120d{m}^3$

$V_1=160d{m}^3$

$V_2=?$

$T_1={91}^{\circ }C+273=364K,T_2={0.00}^{\circ }+273=273K$

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

$V_2=V_1\times \frac{T_2}{T_1}$

$V_2=160d{m}^3\times 273K/364K=120d{m}^3$