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Question

A sample of pure PCl5 was introduced into an evacuated vessel at 473 K. After equilibrium was attained, concentration of PCl5 was found to be 0.5×101mol L1. If value of Kc is 8.3×103, what are the concentrations of PCl3 and Cl2 at equilibrium?
PCl5(g)PCl3(g)+Cl2(g)

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Solution

The equilibrium reaction is :
PCl5(g)PCl3(g)+Cl2(g)
Let x M be the equilibrium concentrations of PCl3 and Cl2.
The equilibrium constant expression is:
Kc=[PCl3][Cl2][PCl5]
8.3×103=x×x0.05
x=[PCl3]=[Cl2]=2.04×102M

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