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Standard XII

Chemistry

Gay Lussac's Law, Avagadro's Law

A sample of p...

Question

A sample of pure gas has a density of 1.60 gm/L at temperature of ${26.5}^{0} C$ and pressure of 680.2 mm Hg. Which of the following gases could the sample be?

C H_{4}

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C_{2} H_{6}

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C O_{2}

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X e

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Solution

The correct option is C $C O_{2}$
Density of a gas is given by:

$d = \frac{P M}{R T} \Rightarrow M = \frac{d R T}{P} = \frac{1.6 \times 0.0821 \times 299.5}{\frac{680.2}{760}} = 44$

$∴ C O_{2}$ is the answer.

Hence, the correct option is $C$

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A sample of pure gas has a density of 1.60 gm/L at temperature of 26.50C and pressure of 680.2 mm Hg. Which of the following gases could the sample be?

The correct option is C CO2Density of a gas is given by:d=PMRT⇒M=dRTP=1.6×0.0821×299.5680.2760=44∴CO2 is the answer.Hence, the correct option is C

A sample of pure gas has a density of 1.60 gm/L at temperature of ${26.5}^{0} C$ and pressure of 680.2 mm Hg. Which of the following gases could the sample be?

The correct option is C $C O_{2}$
Density of a gas is given by:

$d = \frac{P M}{R T} \Rightarrow M = \frac{d R T}{P} = \frac{1.6 \times 0.0821 \times 299.5}{\frac{680.2}{760}} = 44$

$∴ C O_{2}$ is the answer.

Hence, the correct option is $C$