You visited us 1 times! Enjoying our articles? Unlock Full Access!

Dalton's Law of Partial Pressures

A sample of p...

Question

A sample of pure $N O_{2}$ gas healed lo 1000 K decomposes.
$N O_{2} (g) ⇋ 2 N O (g) + O_{2} (g)$
The equillibrium constant $K_{P}$ is 100atm. Analysis shows that the partial pressure of $O_{2}$ is 0.25 atm at equillibrium. The partial pressure of $N O_{2}$ at equillibrium is:

0.03

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.25

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.0245

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.04

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 0.03
$2 N O_{2} (g) ⇋ 2 N O (g) + O_{2} (g)$
Analysis shows that the partial pressure of $O_{2}$ is 0.25 atm at equilibrium. The partial pressure of $N O$ at equilibrium $2 \times$ the partial pressure of $O_{2}$ $2 \times 0.25 = 0.50$ atm.
The equillibrium constant $K_{P}$ is 100 atm.
$K_{p} = \frac{P_{N O}^{2} \times P_{O 2}}{P_{N O 2}^{2}}$
$100 = \frac{(0.50)^{2} \times 0.25}{P_{N O 2}^{2}}$
$P_{N O 2}^{2} = 0.000625$
$P_{N O 2} = 0.025 ≃ 0.03$
The partial pressure of $N O_{2}$ at equilibrium is 0.03 atm.

Suggest Corrections

Similar questions

Q. At

1000

K, a sample of pure

N O_{2}

gas decomposes as:

2 N O_{2} (g) ⇌ 2 N O (g) + O_{2} (g)

The equilibrium constant

K_{p}

156.25

atm. Analysis shows that the partial pressure

0.25

atm at equilibrium. The partial pressure of

N O_{2}

at equilibrium is:

Q. A sample of pure

N O_{2}

gas heated to

1000 K

decomposes:

2 N O_{2} (g) ⇌ 2 N O (g) + O_{2} (g)

. The equilibrium constant

K_{P}

100 a t m

. Analysis shows that the partial pressure of

O_{2}

0.25 a t m

at equilibrium. The partial pressure of

N O_{2}

at equilibrium is:

Q. A sample of pure

N O_{2}

gas heated to 1000k decomposes :

2 N O_{2} (g) ⇌ 2 N O (g) +)_{2} (g)

. The equilibrium constant

K_{p}

is 100 atm . Analysis shows that the partial pressure of

O_{2}

is 0.25 atm at equilibrium. The partial pressure of

N O_{2}

at equilibrium is:

Q. 5 mol

P C l_{5}

(g) an one mole

N_{2}

gas is placed in a closed vessel. at equillibrium

P C l_{5}

(g) decomposes by 20% and total pressure in the container is found to be 1 atm. the

k_{P}

for the equillibrium

P C l_{5} (g) ⇋ P C l_{3} (g) + C l_{2} (g)

is:

Q. For the equillibrium

C (s) + C O_{2} (g) ⇋ 2 C O (g)

K_{p} = 63 a t m

a t 1000 K

.
If at equillibrium

P_{C O} = 10 P_{C O_{2}}

then total pressure at equillibrium is :

Join BYJU'S Learning Program

A sample of pure NO2 gas healed lo 1000 K decomposes.NO2(g)⇋2NO(g)+O2(g)The equillibrium constant KP is 100atm. Analysis shows that the partial pressure of O2 is 0.25 atm at equillibrium. The partial pressure of NO2 at equillibrium is:

A sample of pure $N O_{2}$ gas healed lo 1000 K decomposes.
$N O_{2} (g) ⇋ 2 N O (g) + O_{2} (g)$
The equillibrium constant $K_{P}$ is 100atm. Analysis shows that the partial pressure of $O_{2}$ is 0.25 atm at equillibrium. The partial pressure of $N O_{2}$ at equillibrium is: