A sample of uranium from moon contains equal number of atoms of uranium and lead $(t_{1 / 2} f o r_{92} U = 4.5 \times 10^{9})$ years. The age of rock would be:

4.5 \times 10^{9}

years

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9.0 \times 10^{9}

years

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13.5 \times 10^{9}

years

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2.25 \times 10^{9}

years

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Solution

The correct option is A $4.5 \times 10^{9}$ years
As rock contains equal number of uranium and lead atoms. It means exactly half of uranium converts into lead and so, age of rock will be equal to $t_{1 / 2} = 4.5 \times 10^{9}$ years.

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A sample of uranium from moon contains equal number of atoms of uranium and lead (t1/2for92U=4.5×109) years. The age of rock would be:

The correct option is A 4.5×109 yearsAs rock contains equal number of uranium and lead atoms. It means exactly half of uranium converts into lead and so, age of rock will be equal to t1/2=4.5×109 years.

A sample of uranium from moon contains equal number of atoms of uranium and lead $(t_{1 / 2} f o r_{92} U = 4.5 \times 10^{9})$ years. The age of rock would be:

The correct option is A $4.5 \times 10^{9}$ years
As rock contains equal number of uranium and lead atoms. It means exactly half of uranium converts into lead and so, age of rock will be equal to $t_{1 / 2} = 4.5 \times 10^{9}$ years.