Question

A sample space S is given as S = {1, 2, 3, 4, 5,6, 7}
Following events are described for this sample space.
Event X = {1,2,3}
Y = {3,4,5}
Z = {5,6,}
Events X , Y and Z are not exhaustive events because event X and event Y have an element in common

• A. True
• B. False

Answer 1

The correct option is B False

Look for events to be exhaustive there is only one condition that their union should give sample space. No such condition that they should have no element in common exists. Yes the events are not exhaustive because their union does not give the sample space, not because they have elements in common. So the reason given in the statement is wrong.