A sand layer found at sea floor under 20m water depth is characterized with relative density = 40%, maximum void ratio = 1.0, minimum void ratio = 0.5, and specific gravity of soil solids = 2.67. Assume the specific gravity of sea water to be 1.03 and the unit weight of fresh water to be 9.81 kN/ $m^{3}$ .

What would be the change in the effective stress (rounded off to the nearest integer value of kPa) at 30 m depth into the sand layer, if the sea water level permanently rise by 2m?

19 kPa

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0 kPa

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21 kPa

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22 kPa

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Solution

The correct option is B 0 kPa
Effective stress at 30m depth when water level rises by 2m.

$¯ ¯ ¯ σ = γ_{s u b . H}^{'}$

= 8.934 $\times 30 = 268.02$

Change in effective stress

$Δ ¯ ¯ ¯ σ = 268 - 268 = 0$

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The correct option is B 0 kPaEffective stress at 30m depth when water level rises by 2m. ¯¯¯σ=γ′sub.H = 8.934 ×30=268.02 Change in effective stress Δ¯¯¯σ=268−268=0

The correct option is B 0 kPa
Effective stress at 30m depth when water level rises by 2m.

$¯ ¯ ¯ σ = γ_{s u b . H}^{'}$

= 8.934 $\times 30 = 268.02$

Change in effective stress

$Δ ¯ ¯ ¯ σ = 268 - 268 = 0$