A sand sample has a bulk density of $20 k N / m^{3}$ and a degree of saturation of 70%. If the specific gravity of soil grains is 2.65, the value of critical hydraulic gradient for the soil will be

1.02

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1.05

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1.10

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1.15

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Solution

The correct option is C 1.10
$H y d r a u l i c G r a d i e n t, i_{c r} = \frac{G - 1}{1 + e}$

$B u l k d e n s i t y = \frac{(G + S e) γ_{w}}{1 + e}$

$20 = \frac{(2.65 + 0.7 e)}{1 + e} \times 10$

$20 + 20 e = 26.5 + 7 e$

$e = 0.5$

$\Rightarrow$ $6.5 = 13 e$

$S o, i_{c r} = \frac{2.65 - 1}{1 + 0.5} = \frac{1.65}{1.5}$

$i_{c r} = 1.1$

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A sand sample has a bulk density of 20kN/m3 and a degree of saturation of 70%. If the specific gravity of soil grains is 2.65, the value of critical hydraulic gradient for the soil will be

The correct option is C 1.10Hydraulic Gradient, icr=G−11+e Bulk density =(G+Se)γw1+e 20=(2.65+0.7e)1+e×10 20+20e=26.5+7e e=0.5 ⇒ 6.5=13e So,icr=2.65−11+0.5=1.651.5 icr=1.1

A sand sample has a bulk density of $20 k N / m^{3}$ and a degree of saturation of 70%. If the specific gravity of soil grains is 2.65, the value of critical hydraulic gradient for the soil will be