A satellite in a force-free space sweeps stationary interplanetary dust at a rate $\frac{d M}{d t} = β v$ . The acceleration of satellite is?

- β v^{2} / M

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- β v^{2} / 2 M

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- β v^{2}

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- M β / v^{2}

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Solution

The correct option is D $- β v^{2} / M$
Thrust on the satellite $F = - v \cdot \frac{d M}{d t}$
$= - v \cdot (β v) = - β v^{2}$
Acceleration $= \frac{F o r c e}{m a s s} = - \frac{β v^{2}}{M}$ .

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A satellite in a force-free space sweeps stationary interplanetary dust at a rate dMdt=βv. The acceleration of satellite is?

The correct option is D −βv2/MThrust on the satellite F=−v⋅dMdt=−v⋅(βv)=−βv2Acceleration =Forcemass=−βv2M.

A satellite in a force-free space sweeps stationary interplanetary dust at a rate $\frac{d M}{d t} = β v$ . The acceleration of satellite is?

The correct option is D $- β v^{2} / M$
Thrust on the satellite $F = - v \cdot \frac{d M}{d t}$
$= - v \cdot (β v) = - β v^{2}$
Acceleration $= \frac{F o r c e}{m a s s} = - \frac{β v^{2}}{M}$ .