A satellite in force-free space sweeps stationary interplanetary dust at a rate $(d m / d t) = v$ . The acceleration of satellite is:

2 v^{2} / m

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v^{2} / m

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v^{2} / 2 m

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v^{2}

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Solution

The correct option is B - $v^{2} / m$
Due to mass loss,
The force gain provided by conservation of momentum is given by
Thrust on the satellite
$F = - υ \frac{d M}{d t}$
$= - υ \times υ = - υ^{2}$
Hence acceleration is given by,
$\Rightarrow \frac{E}{M} = - \frac{υ^{2}}{m}$

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A satellite in force-free space sweeps stationary interplanetary dust at a rate (dm/dt)=v . The acceleration of satellite is:

The correct option is B -v2/mDue to mass loss,The force gain provided by conservation of momentum is given by Thrust on the satelliteF=−υdMdt=−υ×υ=−υ2Hence acceleration is given by,⇒EM=−υ2m

A satellite in force-free space sweeps stationary interplanetary dust at a rate $(d m / d t) = v$ . The acceleration of satellite is:

The correct option is B - $v^{2} / m$
Due to mass loss,
The force gain provided by conservation of momentum is given by
Thrust on the satellite
$F = - υ \frac{d M}{d t}$
$= - υ \times υ = - υ^{2}$
Hence acceleration is given by,
$\Rightarrow \frac{E}{M} = - \frac{υ^{2}}{m}$