A satellite is geostationary in a particular orbit. It is allowed to go to another orbit having an orbital radius 2 times that of the earlier orbit from the centre of the earth. The time period in the second orbit is
A
48 hrs
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B
24 hrs
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C
48√2 hrs
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D
24√2 hrs
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Solution
The correct option is D48√2 hrs Time period is related to orbit radius as T2∝R3 ⇒T21T22=R31R32 Given R1=R and R2=2R T21T22=(R2R)3=18 ⇒T2=T1√8=24×2√2=48√2 hours