A satellite is in a circular orbit around the earth has kinetic energy Ek . Minimum amount of energy that is added so that it escapes the earth's gravitational field is:
A
Ek
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B
Ek /2
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C
Ek /4
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D
2 Ek
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Solution
The correct option is D 2 Ek T.E at circular orbit,
T.E=K.E+P.E
=Ek−GMmr
But Ek=12mv2=12m(GMr)2=GMm2r
T.E=GMm2r]GMmr=−GMmr
To escapre the orbit, an energy of GMmr should be given.