A satellite is launched into circular orbit of radius R around the earth while a second satellite is launched into an orbit of Radius 1.02 R. The percentage change in the time periods of the two satellite is
A
0.7
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B
1
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C
1.5
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D
3
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Solution
The correct option is D 3 From kepler's law T2∝r3
By applying small approximation method,
⟹2(ΔTT×100)=3(Δrr×100)
⟹2(ΔTT×100)=3(1.02R−RR×100)
⟹2(ΔTT×100)=3×0.02×100
⟹2(ΔTT×100)=3×2
⟹ΔTT×100= Percentage difference in the time period =3