Question

A satellite is moving in a circular orbit around earth with a speed $V$, If its mass is m, then its total energy will be.

• A. $\frac{3}{4}m{v}^2$
• B. $m{v}^2$
• C. $\frac{1}{2}m{v}^2$
• D. $-\frac{1}{2}m{v}^2$

Answer 1

Answer: (D)

$-\frac{1}{2}m{v}^2$

$T.E=K.E+P.E=\frac{1}{2}m{v}^2+(-\frac{GMm}{r})$

But $v^2=\frac{GM}{r}$

$T.E=\frac{1}{2}m{v}^2+(-m{v}^2)$

$⟹T.E=-\frac{1}{2}m{v}^2$