Question

A satellite is revolving around the earth in a circular orbit of radius a with velocity $v_0$. A particle is projected from it in backward direction with relative velocity $v=(\sqrt{\frac{7}{6}}+1)v_0$ . If maximum and minimum distances achieved by the particle from centre of earth are $r_{max}$ and $r_{min}$ respectively, then

• A. $r_{max}=\frac{7}{5}a$
• B. $r_{min}=\frac{3}{7}a$
• C. $r_{min}=a$
• D. $r_{max}=\frac{5}{3}a$

Answer 1

Answer: (A), (C)

$r_{min}=a$

Use Angular momentum conservation and Mechanical energy conservation