Question

A satellite moves in a circle around the earth. The radius of this circle is equal to one half the radius of the moon's orbit. This satellite completes one revolution in

• A. $\frac{1}{2}$ lunar month.
• B. $2\sqrt{2}$ lunar month.
• C. $2^{\frac{-3}{2}}$ lunar month.
• D. $2^{\frac{-2}{3}}$ lunar month.

Answer 1

The correct option is C

$2^{\frac{-3}{2}}$ lunar month.

From Kepler's law of period

${\left(\frac{T_1}{T_2}\right)}^2={\left(\frac{R_1}{R_2}\right)}^3$

= $2^{\frac{-3}{2}}$ of one lunar month.