A satellite moves in a circular orbit around earth. The radius of this orbit is one half that of moon's orbit. The satellite completes one revolution in:

(2) ^3/2 lunar month

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(2) ³ lunar month

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(2) ^2/3 lunar month

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(2)^1/2 lunar month

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Solution

The correct option is A. (2) ^2/3 lunar month
According to the Kepler's law of periods,
$T^{2} \propto r^{3}$
where T = Time period of the orbiting planet
r = Radius of the orbit
Let the radius of the moon's orbit be a, so that the radius of the satellite's orbit is a/2.

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A satellite moves in a circular orbit around earth. The radius of this orbit is one half that of moon's orbit. The satellite completes one revolution in:

The correct option is A. (2) 2/3 lunar monthAccording to the Kepler's law of periods,T2∝r3where T = Time period of the orbiting planetr = Radius of the orbitLet the radius of the moon's orbit be a, so that the radius of the satellite's orbit is a/2.

The correct option is A. (2) ^2/3 lunar month
According to the Kepler's law of periods,
$T^{2} \propto r^{3}$
where T = Time period of the orbiting planet
r = Radius of the orbit
Let the radius of the moon's orbit be a, so that the radius of the satellite's orbit is a/2.