A satellite of mass 500 kg revolves around the earth in a circular path. If the distance between the satellite and the centre of the earth is 30000 km, find the gravitational force exerted by the earth on the satellite.

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Solution

F = $\frac{G M}{r^{2}}$ = $\frac{6.673 \times 10^{- 11} \times 500}{3 \times 10^{7}}$ = 1112.16 $\times$ $10^{- 18}$

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A satellite of mass 500 kg revolves around the earth in a circular path. If the distance between the satellite and the centre of the earth is 30000 km, find the gravitational force exerted by the earth on the satellite.

F = GMr2 = 6.673×10−11×5003×107 = 1112.16 × 10−18

F = $\frac{G M}{r^{2}}$ = $\frac{6.673 \times 10^{- 11} \times 500}{3 \times 10^{7}}$ = 1112.16 $\times$ $10^{- 18}$