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Question

A satellite of mass m revolves around the earth of radius R at a height x from its surface. If g is the acceleration due to gravity on the surface of the earth, the orbital speed of the satellite is

A
gx
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B
gRRx
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C
gR2Rx
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D
gR2R+x
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Solution

The correct option is D gR2R+x
We have:
mv2R+x=GMm(R+x)2v=GMR+x=GMR2×R2R+x=gR2R+x
because the gravitational force provides the centripetal force for revolution.

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