A satellite orbiting the Earth at 400 km above the surface of the Earth has a 2 m long antenna oriented perpendicular to the Earth-s surface- At the equator the Earth-s magnetic field is 8 - 10-5 T and is horizontal- Assuming the orbit to the circular- find emf induced across the ends of the antenna-Given radius of earth Re-6400 Km

The correct option is A 1.2 V We know mv_0^2r=GMmr^2 Velocity of satellite v_0 =R √(g(R+h))=7.68× 10^3 m/s Induced emf = Blv_0 = 8 × 10^ 5× ...

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Standard XII

Physics

Motional EMF

A satellite o...

Question

A satellite orbiting the Earth at $400$ $k m$ above the surface of the Earth has a $2$ $m$ long antenna oriented perpendicular to the Earth's surface. At the equator the Earth's magnetic field is $8 \times 10^{- 5} T$ and is horizontal. Assuming the orbit to the circular, find emf induced across the ends of the antenna.(Given radius of earth $R_{e} = 6400 K m$ )

1.3 V

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1.2 V

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1.0 V

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0.12 V

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Solution

The correct option is A $1.2 V$
We know
$\frac{m v_{0}^{2}}{r} = \frac{G M m}{r^{2}}$
Velocity of satellite $v_{0} = R \sqrt{\frac{g}{(R + h)}} = 7.68 \times 10^{3} m / s$
Induced $e m f = B l v_{0} = 8 \times 10^{- 5} \times 2 \times 7.68 \times 10^{3} = 1.2 V$

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The correct option is A 1.2VWe knowmv20r=GMmr2Velocity of satellite v0=R√g(R+h)=7.68×103m/sInduced emf=Blv0=8×10−5×2×7.68×103=1.2V

The correct option is A $1.2 V$
We know
$\frac{m v_{0}^{2}}{r} = \frac{G M m}{r^{2}}$
Velocity of satellite $v_{0} = R \sqrt{\frac{g}{(R + h)}} = 7.68 \times 10^{3} m / s$
Induced $e m f = B l v_{0} = 8 \times 10^{- 5} \times 2 \times 7.68 \times 10^{3} = 1.2 V$