A satellite which is geostationary in a particular orbit is taken to another orbit. Its distance from the centre of earth in new orbit is 2 times that of the earlier orbit. The time period in the second orbit is

4.8 hours

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$48 \sqrt{2}$ hours

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24 hours

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$24 \sqrt{2}$ hours

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Solution

The correct option is B
$48 \sqrt{2}$ hours

$T \propto r^{\frac{3}{2}}$ . If r becomes double then time period will becomes $(2)^{\frac{3}{2}}$ times.
The time period of a geostationary satellite is 24 hours, So new time period will be $24 \times 2 \sqrt{2} h r i . e . T = 48 \sqrt{2}$

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A satellite which is geostationary in a particular orbit is taken to another orbit. Its distance from the centre of earth in new orbit is 2 times that of the earlier orbit. The time period in the second orbit is

The correct option is B 48√2 hours T∝r32. If r becomes double then time period will becomes (2)32 times. The time period of a geostationary satellite is 24 hours, So new time period will be 24×2√2 hr i.e. T=48√2

The correct option is B
$48 \sqrt{2}$ hours

$T \propto r^{\frac{3}{2}}$ . If r becomes double then time period will becomes $(2)^{\frac{3}{2}}$ times.
The time period of a geostationary satellite is 24 hours, So new time period will be $24 \times 2 \sqrt{2} h r i . e . T = 48 \sqrt{2}$