wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A saturated solution of copper sulphate was prepared at 60°C and put in three tubes X, Y and Z.

(i) Tube X is heated to 95°C.

(ii) Tube Y is cooled to 25°C.

(iii) 10 ml. of water is added to tube Z.


Open in App
Solution

(a) A saturated solution of copper sulphate was prepared at 60°C and when tube X is heated to 95°C. the colour of crystals before heating was blue, which changes the colour of crystals after heating to white.

CuSO4.5H2OCuSO4+5H2Ocoppersulphatecrystal

(b) When tube Y is cooled at 25°C, water will evaporate slowly and crystals of copper sulphate will be formed.

(c) When 10 ml. of water is added to tube Z. the disappeared blue colour of copper sulphate solution will appear again.


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Hydrogen and Reactivity Series
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon