A saturated undisturbed sample from a clay strata has moisture content of 22.22% and specific weight of 2.7. Assuming $γ_{w} = 10 k N / m^{3}$ , the void ratio and the saturated unit weight of the clay, respectively are

0.6 a n d 16.875 k N / m^{3}

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0.3 a n d 20.625 k N / m^{3}

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0.6 a n d 20.625 k N / m^{3}

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0.3 a n d 16.975 k N / m^{3}

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Solution

The correct option is C $0.6 a n d 20.625 k N / m^{3}$
Moisture content,

w = 22.22%

$G_{s} = 2.7$

$γ_{w} = 10 k N / m^{3}$

Clay sample is saturated so,

S = 1

$W e k n o w, S e = w G_{s}$

$\Rightarrow e = \frac{0.2222 \times 2.7}{1} = 0.6$

Saturated unit weight

$γ_{t} = \frac{(G_{s} + S e)}{1 + e} γ_{w}$

$= \frac{(2.7 + 0.6)}{1 + 0.6} \times 10$

$= 20.625 k N / m^{3}$

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A saturated undisturbed sample from a clay strata has moisture content of 22.22% and specific weight of 2.7. Assuming γw=10kN/m3, the void ratio and the saturated unit weight of the clay, respectively are

The correct option is C 0.6 and 20.625 kN/m3Moisture content, w = 22.22% Gs=2.7 γw=10kN/m3 Clay sample is saturated so, S = 1 We know, Se =wGs ⇒e=0.2222×2.71=0.6 Saturated unit weight γt=(Gs+Se)1+eγw =(2.7+0.6)1+0.6×10 =20.625 kN/m3

A saturated undisturbed sample from a clay strata has moisture content of 22.22% and specific weight of 2.7. Assuming $γ_{w} = 10 k N / m^{3}$ , the void ratio and the saturated unit weight of the clay, respectively are