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Question

A schematic diagram is shown where a circuit consisting of a battery of 3 cells of 2 V each, a combination of three resistors of 10 Ω, 20 Ω and 30 Ω connected in parallel, a plug key and an ammeter, all connected in series. Use this circuit to find the value of the following :


(a) Current through each resistor
(b) Total current in the circuit
(c) Total effective resistance of the circuit.
[5 marks]

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Solution

The circuit diagram is as shown below.
(a) Given, voltage of the battery = 2V + 2V + 2V = 6 V
Current through 10 Ω resistance,
I10=V/R=6/10=0.6 A
Current through 20 Ω resistance,
I20=V/R=6/20=0.3 A
Current through 30 Ω resistance,
I20=V/R=6/30=0.2 A
[2 marks]
(b) Total current in the circuit, I=I10+I20+I30
= 0.6 + 0.3 + 0.2 = 1.1 A
[1 mark]
(c) Total resistance of the circuit - As the resistors are connected in parallel,
1/Rp=1/10+1/20+1/30
1/Rp=60/11=5.45 Ω
[2 marks]

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