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Standard VII

Mathematics

Percentages

A school audi...

Question

A school auditorium is $40$ m long, $30$ m broad and $12$ m high. If each student requires $1.2$ $m^{2}$ of the floor area; find the maximum number of students who can be accomodated in this auditorium.

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Solution

Given, $L = 40$ m, $B = 30$ m
Area of auditorium $=$ $A = L \times B$
$A = 40 \times 30$
$A = 1200$
Max number of student on auditorium $=$ Area/minimum area required by $1$ student
$N = \frac{1200}{1.2}$
$N = 1000$
Number of students $= 1000$

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A school auditorium is 40 m long, 30 m broad and 12 m high. If each student requires 1.2 m2 of the floor area; find the maximum number of students who can be accomodated in this auditorium.

Given, L=40 m, B=30 mArea of auditorium = A=L×BA=40×30A=1200Max number of student on auditorium = Area/minimum area required by 1 studentN=12001.2N=1000Number of students =1000

A school auditorium is $40$ m long, $30$ m broad and $12$ m high. If each student requires $1.2$ $m^{2}$ of the floor area; find the maximum number of students who can be accomodated in this auditorium.

Given, $L = 40$ m, $B = 30$ m
Area of auditorium $=$ $A = L \times B$
$A = 40 \times 30$
$A = 1200$
Max number of student on auditorium $=$ Area/minimum area required by $1$ student
$N = \frac{1200}{1.2}$
$N = 1000$
Number of students $= 1000$