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Standard IX

Mathematics

Ratio and Proportion

A school audi...

Question

A school auditorium is 40 m long, 30 m broad and 12 m high. If each student requires 1.2 $m^{2}$ of the floor area, find the maximum number of students who can be accommodated in this auditorium.

790

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980

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1000

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1110

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Solution

The correct option is C 1000
L=40m, B=30m
Area of auditorium=
$A = L \times B$
$A = 40 \times 30$
$A = 1200$
Max no of student on auditorium= Area/minimum area required by 1 student
$N = 1200 / 1.2$
$N = 1000$
No of student=1000

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A school auditorium is 40 m long, 30 m broad and 12 m high. If each student requires 1.2 m2 of the floor area, find the maximum number of students who can be accommodated in this auditorium.

The correct option is C 1000L=40m, B=30mArea of auditorium=A=L×BA=40×30A=1200Max no of student on auditorium= Area/minimum area required by 1 studentN=1200/1.2N=1000No of student=1000

A school auditorium is 40 m long, 30 m broad and 12 m high. If each student requires 1.2 $m^{2}$ of the floor area, find the maximum number of students who can be accommodated in this auditorium.

The correct option is C 1000
L=40m, B=30m
Area of auditorium=
$A = L \times B$
$A = 40 \times 30$
$A = 1200$
Max no of student on auditorium= Area/minimum area required by 1 student
$N = 1200 / 1.2$
$N = 1000$
No of student=1000