Question 11.
A school has 8 periods a day each of 45 minutes duration. How long would each period be, if the school has 9 periods a day, assuming the number of school hours to be the same?

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Solution

Let the duration of each period be x
$\begin{matrix} P e r i o d & 8 & 9 D u r a t i o n o f p e r i o d (i n m i n u t e s) & 45 & x \end{matrix}$
Here the number of periods and the duration of periods are in inverse proportion.

$∴ \frac{8}{9} = \frac{x}{45} \Rightarrow x \times 9 = 8 \times 45 \Rightarrow x = \frac{8 \times 45}{9} = 40 m i n u t e s$
Hence, the duration of each period would be 40 minutes.

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Application of Inverse Proportionality

Standard IX Mathematics

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Question 11. A school has 8 periods a day each of 45 minutes duration. How long would each period be, if the school has 9 periods a day, assuming the number of school hours to be the same?

Let the duration of each period be x Period89Duration of period (in minutes)45x Here the number of periods and the duration of periods are in inverse proportion. ∴ 89=x45⇒ x×9=8×45⇒ x=8×459=40 minutes Hence, the duration of each period would be 40 minutes.

Question 11.
A school has 8 periods a day each of 45 minutes duration. How long would each period be, if the school has 9 periods a day, assuming the number of school hours to be the same?