A school has only three classes which contain 40, 50 and 60 students respectively. The pass percentages of these classes are 10, 20 and 10 respectively. The pass percentage of the school is:

13 \frac{1}{3}

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16 \frac{2}{3}

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Solution

The correct option is A $13 \frac{1}{3}$
$N u m b e r o f p a s s e d c a n d i d a t e s$

$= (\frac{10}{100} \times 40 + \frac{20}{100} \times 50 + \frac{10}{100} \times 60)$

$= (4 + 10 + 6) = 20$

$P a s s e d p e r c e n t a g e = \frac{20}{(40 + 50 + 60)} \times 100$

$= (\frac{20}{150} \times 100) %$ $= 13 \frac{1}{3} %$

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A school has only three classes which contain 40, 50 and 60 students respectively. The pass percentages of these classes are 10, 20 and 10 respectively. The pass percentage of the school is:

The correct option is A 1313Number of passed candidates =(10100×40+20100×50+10100×60) =(4+10+6)=20 Passed percentage=20(40+50+60)×100 =(20150×100)% = 1313%