Question

A school organises a lunch party for teachers. The catering company offers a veggie burger and a roast beef sandwich and charges $\$4.50$ per veggie burger and $\$6.25$ per roast beef sandwich. If $56$ teachers ordered lunch and the school's total bill was $\$308$, and the number of teachers who ordered a veggie burger is $v$, and who ordered a roast beef sandwich is $r$, then the systems of equations which could be used to find $r$ and $v$ is

• A. $\{\begin{array}{c}v+r=308\\ 4.5v+6.25r=56\end{array}$
• B. $\{\begin{array}{c}v+r=56\\ 4.5v+6.25r=308\end{array}$
• C. $\{\begin{array}{c}v+r=56\\ 4.5v+6.25r=\frac{308}{2}\end{array}$
• D. $\{\begin{array}{c}2(v+r)=56\\ 4.5v+6.25r=308\end{array}$

Answer 1

The correct option is B $\{\begin{array}{c}v+r=56\\ 4.5v+6.25r=308\end{array}$

Given in school party roast,

Beef sandwich = 4.50$ each

Veggie burger = 6.25$ each

Total order : beef sandwich + veggie burger = 56

i.e., $r+v=56$ ...(1)

Cost of beef sandwiches $=$4.5 v$

Cost of veggie burger $=$ 6.25 r$

Now, total bill is 308$.

Then,

$4.5v+6.25r=308$ ...(2)