A school team won 6 games this year against 4 games won last year what is the percent increase?

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Solution

The increase in the number of wins (or amount of change) $= 6 - 4 = 2$

Percentage increase
$= \frac{a m o u n t o f c h a n g e}{o r i g i n a l a m o u n t o r b a s e} \times 100$
$= \frac{2}{4} \times 100$

$= 50 %$

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A school team won 6 games this year against 4 games won last year what is the percent increase?

The increase in the number of wins (or amount of change) =6−4=2Percentage increase =amount of changeoriginal amount or base×100=24×100=50%

The increase in the number of wins (or amount of change) $= 6 - 4 = 2$

Percentage increase
$= \frac{a m o u n t o f c h a n g e}{o r i g i n a l a m o u n t o r b a s e} \times 100$
$= \frac{2}{4} \times 100$

$= 50 %$