Question

A scientist proposes a new temperature scale in which the ice point is 25 X (X is the new unit of temperature) and the steam point is 305 X. The specific heat capacity of water in this new scale is (in $Jk{g}^{-1}{X}^{-1}$)

• A. $4.2\times {10}^3$
• B. $3.0\times {10}^3$
• C. $1.2\times {10}^3$
• D. $1.5\times {10}^3$

Answer 1

The correct option is D $1.5\times {10}^3$

The difference between ice point and steam point in old scale(${}^{\circ }C$)=$100$

The difference between ice point and steam point in new scale=$25X-305X=280X$

Hence $1^{\circ }C=280X$
Hence specific heat capacity=$4200\frac{J}{K{g}^{\circ C}}=\frac{4200}{2.8}\frac{J}{Kg-X}$

$=1.5\times {10}^3\frac{J}{Kg-X}$