A scientist records the length of a fast growing creeper on a bar graph. Using the given graph, calculate the average growth percentage of the creeper from one month to the next.

33.33%

No worries! We‘ve got your back. Try BYJU‘S free classes today!

35.22%

No worries! We‘ve got your back. Try BYJU‘S free classes today!

36.11%

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

10%

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 36.11%
Inspecting the situation from one month to the next, we find:

$A p r i l t o M a y :$

$L e n g t h i n A p r i l = 20 f t L e n g t h i n M a y = 30 f t G r o w t h = 30 f t - 20 f t = 10 f t G r o w t h p e r c e n t a g e = \frac{G r o w t h}{I n i t i a l l e n g t h} \times 100 = \frac{10 f t}{20 f t} \times 100 = 50 %$

$M a y t o J u n e :$

$L e n g t h i n M a y = 30 f t L e n g t h i n J u n e = 40 f t G r o w t h = 40 f t - 30 f t = 10 f t G r o w t h p e r c e n t a g e = \frac{G r o w t h}{I n i t i a l l e n g t h} \times 100 = \frac{10 f t}{30 f t} \times 100 \approx 33.33 %$

$J u n e t o J u l y :$

$L e n g t h i n J u n e = 40 f t L e n g t h i n J u l y = 50 f t G r o w t h = 50 f t - 40 f t = 10 f t G r o w t h p e r c e n t a g e = \frac{G r o w t h}{I n i t i a l l e n g t h} \times 100 = \frac{10 f t}{40 f t} \times 100 = 25 %$

$A v e r a g e = \frac{S u m o f t h e v a l u e s}{N u m b e r o f v a l u e s} = \frac{50 % + 33.33 % + 25 %}{3} \approx 36.11 %$

Hence, the average growth percentage of the creeper from one month to the next is 36.11%.

Suggest Corrections

Similar questions

Question 10
To represent the population of different towns using a bar graph, it is convenient to take one unit length to represent one person.

Join BYJU'S Learning Program