Question

A scooter of mass 120 kg is moving with a uniform velocity of 108 km/h. The force required to stop the vehicle in 10 sec is :

• A. 360 N
• B. 720 N
• C. 180 N
• D. $20\times 10.8N$

Answer 1

The correct option is A 360 N

$u=108km/h^2,m=120kg,t=10\sec$

$v=a,$

$v=u+at$

$u=-a\times \left(10/3600\right)$

$a=-\frac{30}{10}m{s}^{-2}=-3m{s}^2$

$f=ma$

$=120\times 3$

$=360N$