Question

A scooter of mass 120 kg is moving with a uniform velocity of 108 km $h^{-1}$.Calculate the force required to stop the vehicle in 0.1 s.

• A. 26000 N
• B. 36000 N
• C. 46000 N
• D. 56000 N

Answer 1

The correct option is B 36000 N

mass of the object $m=120kg$

initial velocity of the object $v=108km/hr=30m/s$

final velocity of the object $=0m/s$

given time= $0.1sec$

therefore force,

force= change in momentum/time taken

$F=(mv-mu)/t$

$F=(120\ast 0-120\ast 30)/0.1$

$F=(0-3600)/0.1$

$F=-3600/0.1$

$F=-36000N$