Question

A scooter of mass 120 kg is moving with a uniform velocity of 108 km/hr. The force required to stop the vehicle in 10 s is:

• A. 260 N
• B. 360 N
• C. 460 N
• D. 560 N

Answer 1

The correct option is B 360 N

Here, initial velocity of the scooter is $u=108km/h=\frac{108\times 1000}{3600}m/s=30m/s$

Using formula, $v=u-at$, $0=30-a\left(10\right)$ or $a=3m/s^2$

Force $F=ma=120\left(3\right)=360N$