CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
255
You visited us 255 times! Enjoying our articles? Unlock Full Access!
Question

A scooter starting from rest moves with a constant acceleration for a time Δ t1, then with a constant velocity for the next Δ t2, and finally with a constant deceleration. A person of mass 50 kg on the scooter, behind the driver manages to stay at rest with respect to the scooter without touching any other part. The force exerted by the seat on the man is

Take g=10m/ s2


A

500 N throughout the journey

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

less than 500 N throughout the journey

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

more than 500 N throughout the journey

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

> 500 N for time t1 and t3, and 500 N for t2,

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D

> 500 N for time t1 and t3, and 500 N for t2,


So when scooter is accelerating the man is also accelerating along with it so friction from the scooter's seat on man is making him move forward.

Also there is a Normal force

N = mg = 500 N

So Net force while accelerating will be (500)2+(fr)2 > 500

Same is true about decelerating

So while accelerating or decelerating the force on man by scooter is more than 500N. When the scooter is going with constant velocity, the man is also going with constant velocity. So 0 acceleration in horizontal direction so no net force in horizontal direction so no friction.

Only Normal N = mg = 500


flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Rubbing It In: The Basics of Friction
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon