A scooter travelling at $10 m/s$ speed up to $20 m/s$ in $4 sec$ . Find the average acceleration of scooter.

5 {m/s}^{2}

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2.5 {m/s}^{2}

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2 {m/s}^{2}

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4 {m/s}^{2}

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Solution

The correct option is B $2.5 {m/s}^{2}$
Acceleration of the train is given by
$a = \frac{Δ v}{Δ t}$
Here, $Δ v = (20 - 10) = 10 m/s$
and $Δ t = 4 s$
$\Rightarrow a = \frac{10}{4} = 2.5 {m/s}^{2}$

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A scooter travelling at 10 m/s speed up to 20 m/s in 4 sec. Find the average acceleration of scooter.

The correct option is B 2.5 m/s2Acceleration of the train is given by a=ΔvΔt Here, Δv=(20−10)=10 m/s and Δt=4 s ⇒ a=104=2.5 m/s2

A scooter travelling at $10 m/s$ speed up to $20 m/s$ in $4 sec$ . Find the average acceleration of scooter.

The correct option is B $2.5 {m/s}^{2}$
Acceleration of the train is given by
$a = \frac{Δ v}{Δ t}$
Here, $Δ v = (20 - 10) = 10 m/s$
and $Δ t = 4 s$
$\Rightarrow a = \frac{10}{4} = 2.5 {m/s}^{2}$