The correct option is B ₹ 38,640
Here, Value of scooter (P) = ₹42,000
Rate of Depreciation (R)= 8%
Time (n) = 1 years
Value of scooter after depreciation (A)
A=(1−R100)n=42000(1−8100)1=42000(1−225)1
=42000(2325)1=42000×2325=₹38,640
Hence, the value of scooter after one year is ₹ 38,640.