A scooter was bought at Rs. 42000 and its value depreciated at the rate of 8% per annum. Find its value after one year.
The correct option is B Rs. 38640
P= value after n years
Let, P0= Purchase price
Rate =8%
Using P=P0(1−r100)n to find the depreciated value.
P=42000×[1−8100]1 (here n=1 )
P=42000×[100−8100]
P=420×92
P=Rs. 38640
The value of scooter after one year will be Rs. 38640