Question

Question 12
A scooter was bought at ₹42,000.Its value depreciated at the rate of 8% per annum. Find its value after one year.

Answer 1

Here, Principal (P) = ₹42,000
Rate of Interest (R)= 8%
Time (n) = 1 years

Amount (A) .
$A={(1-\frac{R}{100})}^n=42000{(1-\frac{8}{100})}^1=42000{(1-\frac{2}{25})}^1$
$=42000{\left(\frac{23}{25}\right)}^1=42000\times \frac{23}{25}=₹38,640$
Hence, the value of scooter after one year is Rs 38,640.