Question

# A scooter was bought at $Rs42000$. Its value depreciated at the rate of $8%$ per annum. Find its value after one year

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Solution

## Principal = Cost price of the scooter = ₹ 42,000Depreciation = 8% of ₹ 42,000 per year= (P x R x T)/100= (42000 x 8 x 1)/100We get,= ₹ 3360Hence, the value after one year = ₹ 42,000 – ₹ 3360 = ₹ 38,640

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