Question

A scooter weighing 150 kg together with its rider moving at 36 km/hr is to take a turn of a radius 30 m. What horizontal force on the scooter is needed to make the turn possible?

Answer 1

Given:
Mass = m = 150 kg
Speed = v = 36 km/hr = 10 m/s
Radius of turn = r = 30 m
Let the horizontal force needed to make the turn be F. We have:
$$\begin{gathered} F=\frac{m{v}^2}{r}=\frac{150\times (10{)}^2}{30} \\ =\frac{150\times 100}{30}=500\mathrm{N} \end{gathered}$$