Question

A scooter weighing $150kg$ together with its rider moving at $36km/hr$ is to take a turn of radius $30m$

If the horizontal force needed for the turn in the previous problem is to be supplied by the normal force by the road, what should be the proper angle of banking?

Answer 1

$Rcos\theta =mg.......\left(i\right)$

$Rsin\theta =\frac{m{v}^2}{r}.....\left(ii\right)$

Dividing equation $i$ with equation $ii$ we get,

devide = $tan\theta =\frac{m{v}^2}{rmg}=\frac{v^2}{rg}$
$v=36km/hr=10m/sec$ & $r=30m$
$tan\theta =\frac{v^2}{rg}=\frac{100}{30\times 10}=\frac{1}{3}$
$\theta =ta{n}^{-1}\left(\frac{1}{3}\right)$