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Question

A scooterist is approaching a circular turn of radius 80 m. He reduced his speed from 27 kmh1 at constant rate of 0.5 ms2. Find net acceleration and angle made by it wrt tangential deceleration

A
0.86 ms2,54
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B
0.68 ms2,45
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C
1.0 ms2,45
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D
0.5 ms2,45
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Solution

The correct option is A 0.86 ms2,54

Centripetal acceleration
ar=v2r=(27×10003600)280
=7.5×7.580=0.703 ms2
Net acceleration, a=a2r+a2t
where at = tangential deceleration =0.5 ms2

a=0.7032+0.52=0.86 ms2
and
θ=tan1arat=tan10.7030.5=54

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