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Question

A screw factory has two machines, the M1, which is old, and does 75% of all the screws, and the M2, newer but small, that does 25% of the screws. The M1 does 4% of defective screws, while the M2 just does 2% of defective screws. If we choose a screw at random: what is the probability that it turns out to be defective?

A
0.035
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B
0.045
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C
0.015
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D
None of these
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Solution

The correct option is A 0.035
The diagrammatic representation of the problem is shown above.
We consider the following events;
M1= being produced by machine 1.
Therefore, ¯¯¯¯¯¯¯¯¯M1=M2 being produced by machine 2.
D= defective screw.
In the diagram we can see the red branch in which we are interested.
The top branch being produced by machine 1 and being defective has probability 75100×4100=0.75×0.04=0.03.
The bottom branch being produced by machine 2 and being defective has probability 25100×2100=0.25×0.02=0.005.
Therefore, the probability of being defective is 0.03+0.005=0.035.

750075_583680_ans_2937f7cfcfea44c6a648b68ccc4b9f0d.jpg

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