A screw gauge has 200 equal divisions marked along the circumference of the disc and one full rotation of the disc advances on the main scale by 0.05 cm. The least count of the screw gauge is :

2.5 \times 10^{- 4} c m

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2.5 \times 10^{- 3} c m

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6.25 \times 10^{- 4} c m

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6.25 \times 10^{- 3} c m

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Solution

The correct option is A $2.5 \times 10^{- 4} c m$
Least count $= \frac{P i t c h}{N o . o f d i v i s i o n s} = \frac{0.05}{200} = 2.5 \times 10^{- 4} c m$

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A screw gauge has 200 equal divisions marked along the circumference of the disc and one full rotation of the disc advances on the main scale by 0.05 cm. The least count of the screw gauge is :

The correct option is A 2.5×10−4cmLeast count =PitchNo.of divisions=0.05200=2.5×10−4cm

The correct option is A $2.5 \times 10^{- 4} c m$
Least count $= \frac{P i t c h}{N o . o f d i v i s i o n s} = \frac{0.05}{200} = 2.5 \times 10^{- 4} c m$