A screw gauge has 50 divisions on its circular scale and its screw moves by 1 mm on turning it by two revolutions. When the flat end of the screw is in contact with the stud, the zero of circular scale lies below the baseline and 4th division of circular scale is in line with the baseline. Find the zero error of the screw gauge.

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Solution

The situation given in the problem is similar to that of shown in the figure. This is called positive zero error case. According to the problem, the baseline and 4th division of circular scale is in line with the base line. And the least count of this screw gauge is 1/100=0.01. So the zero error of the gauge is $4 \times 0.01 = 0.04$

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